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1131101113332 = 22394258426111
BaseRepresentation
bin10000011101011010111…
…000010100101111110100
311000010120101022000122010
4100131122320110233310
5122012443341111312
62223342022204220
7144501511554231
oct20353270245764
94003511260563
101131101113332
113a67740aa843
1216326b583670
138287c320a08
143ca61c60788
151e6510d093c
hex1075ae14bf4

1131101113332 has 12 divisors (see below), whose sum is σ = 2639235931136. Its totient is φ = 377033704440.

The previous prime is 1131101113309. The next prime is 1131101113379. The reversal of 1131101113332 is 2333111011311.

It is a tau number, because it is divible by the number of its divisors (12).

It is a junction number, because it is equal to n+sod(n) for n = 1131101113299 and 1131101113308.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47129213044 + ... + 47129213067.

Almost surely, 21131101113332 is an apocalyptic number.

1131101113332 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

1131101113332 is an abundant number, since it is smaller than the sum of its proper divisors (1508134817804).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1131101113332 is a wasteful number, since it uses less digits than its factorization.

1131101113332 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 94258426118 (or 94258426116 counting only the distinct ones).

The product of its (nonzero) digits is 162, while the sum is 21.

Adding to 1131101113332 its reverse (2333111011311), we get a palindrome (3464212124643).

The spelling of 1131101113332 in words is "one trillion, one hundred thirty-one billion, one hundred one million, one hundred thirteen thousand, three hundred thirty-two".

Divisors: 1 2 3 4 6 12 94258426111 188516852222 282775278333 377033704444 565550556666 1131101113332