1131101320013 has 8 divisors (see below), whose sum is σ = 1293776269632. Its totient is φ = 968698632096.

The previous prime is 1131101320009. The next prime is 1131101320021. The reversal of 1131101320013 is 3100231011311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1131101320013 - 2² = 1131101320009 is a prime.

It is a super-2 number, since 2×1131101320013² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1131101319973 and 1131101320000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1131101320093) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 68056520 + ... + 68073137.

It is an arithmetic number, because the mean of its divisors is an integer number (161722033704).

Almost surely, 2^{1131101320013} is an apocalyptic number.

It is an amenable number.

1131101320013 is a deficient number, since it is larger than the sum of its proper divisors (162674949619).

1131101320013 is a wasteful number, since it uses less digits than its factorization.

1131101320013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 136130851.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 1131101320013 its reverse (3100231011311), we get a palindrome (4231332331324).

The spelling of 1131101320013 in words is "one trillion, one hundred thirty-one billion, one hundred one million, three hundred twenty thousand, thirteen".