11311101000211 has 4 divisors (see below), whose sum is σ = 11311142185000. Its totient is φ = 11311059815424.

The previous prime is 11311101000179. The next prime is 11311101000229. The reversal of 11311101000211 is 11200010111311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11311101000211 - 2⁵ = 11311101000179 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11311101000191 and 11311101000200.

It is not an unprimeable number, because it can be changed into a prime (11311101000811) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20177646 + ... + 20730643.

It is an arithmetic number, because the mean of its divisors is an integer number (2827785546250).

Almost surely, 2^{11311101000211} is an apocalyptic number.

11311101000211 is a deficient number, since it is larger than the sum of its proper divisors (41184789).

11311101000211 is an equidigital number, since it uses as much as digits as its factorization.

11311101000211 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 41184788.

The product of its (nonzero) digits is 6, while the sum is 13.

Adding to 11311101000211 its reverse (11200010111311), we get a palindrome (22511111111522).

The spelling of 11311101000211 in words is "eleven trillion, three hundred eleven billion, one hundred one million, two hundred eleven", and thus it is an aban number.