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11311101312314 = 25655550656157
BaseRepresentation
bin1010010010011001001000…
…1011001111110100111010
31111001022221002122210122212
42210212102023033310322
52440310113413443224
640020125340215122
72245125430541006
oct244462213176472
944038832583585
1011311101312314
1136710138a1491
121328200b3a4a2
1364082b1601cb
142b1662bdb706
1514936376ad0e
hexa49922cfd3a

11311101312314 has 4 divisors (see below), whose sum is σ = 16966651968474. Its totient is φ = 5655550656156.

The previous prime is 11311101312307. The next prime is 11311101312377. The reversal of 11311101312314 is 41321310111311.

11311101312314 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 7529892724225 + 3781208588089 = 2744065^2 + 1944533^2 .

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 11311101312314.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2827775328077 + ... + 2827775328080.

Almost surely, 211311101312314 is an apocalyptic number.

11311101312314 is a deficient number, since it is larger than the sum of its proper divisors (5655550656160).

11311101312314 is an equidigital number, since it uses as much as digits as its factorization.

11311101312314 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5655550656159.

The product of its (nonzero) digits is 216, while the sum is 23.

Adding to 11311101312314 its reverse (41321310111311), we get a palindrome (52632411423625).

The spelling of 11311101312314 in words is "eleven trillion, three hundred eleven billion, one hundred one million, three hundred twelve thousand, three hundred fourteen".

Divisors: 1 2 5655550656157 11311101312314