| Base | Representation |
|---|---|
| bin | 10000011101011011011… |
| … | …011011010000011110100 |
| 3 | 11000010121000121021021100 |
| 4 | 100131123123122003310 |
| 5 | 122013003214411012 |
| 6 | 2223342551250100 |
| 7 | 144501653000115 |
| oct | 20353333320364 |
| 9 | 4003530537240 |
| 10 | 1131110310132 |
| 11 | 3a6779311500 |
| 12 | 163272679930 |
| 13 | 828811c0aca |
| 14 | 3ca6317620c |
| 15 | 1e651cea8dc |
| hex | 1075b6da0f4 |
1131110310132 has 216 divisors, whose sum is σ = 3351939114888. Its totient is φ = 320240701440.
The previous prime is 1131110310107. The next prime is 1131110310199. The reversal of 1131110310132 is 2310130111311.
1131110310132 is a `hidden beast` number, since 1 + 1 + 311 + 10 + 310 + 1 + 32 = 666.
It can be written as a sum of positive squares in 4 ways, for example, as 104203713636 + 1026906596496 = 322806^2 + 1013364^2 .
It is a super-3 number, since 3×11311103101323 (a number of 37 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 10089378 + ... + 10200870.
It is an arithmetic number, because the mean of its divisors is an integer number (15518236643).
Almost surely, 21131110310132 is an apocalyptic number.
1131110310132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1131110310132, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1675969557444).
1131110310132 is an abundant number, since it is smaller than the sum of its proper divisors (2220828804756).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1131110310132 is a wasteful number, since it uses less digits than its factorization.
1131110310132 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 111679 (or 111663 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 18.
Adding to 1131110310132 its reverse (2310130111311), we get a palindrome (3441240421443).
The spelling of 1131110310132 in words is "one trillion, one hundred thirty-one billion, one hundred ten million, three hundred ten thousand, one hundred thirty-two".
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