Base | Representation |
---|---|
bin | 110100101010111110… |
… | …1000110011001001111 |
3 | 101210221220201211121222 |
4 | 1221111331012121033 |
5 | 3323122433330111 |
6 | 123543530113555 |
7 | 11113000406642 |
oct | 1512575063117 |
9 | 353856654558 |
10 | 113111230031 |
11 | 43a743822a8 |
12 | 19b0887b8bb |
13 | a887c57617 |
14 | 56904a1a59 |
15 | 2e2030d7db |
hex | 1a55f4664f |
113111230031 has 2 divisors, whose sum is σ = 113111230032. Its totient is φ = 113111230030.
The previous prime is 113111230021. The next prime is 113111230061. The reversal of 113111230031 is 130032111311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 113111230031 - 230 = 112037488207 is a prime.
It is a super-2 number, since 2×1131112300312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 113111229991 and 113111230009.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113111230021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56555615015 + 56555615016.
It is an arithmetic number, because the mean of its divisors is an integer number (56555615016).
Almost surely, 2113111230031 is an apocalyptic number.
113111230031 is a deficient number, since it is larger than the sum of its proper divisors (1).
113111230031 is an equidigital number, since it uses as much as digits as its factorization.
113111230031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 113111230031 its reverse (130032111311), we get a palindrome (243143341342).
The spelling of 113111230031 in words is "one hundred thirteen billion, one hundred eleven million, two hundred thirty thousand, thirty-one".
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