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113111330112000 = 2932531137563857
BaseRepresentation
bin11001101101111111001000…
…101001101100001000000000
3112211111100010002001201120200
4121231333020221230020000
5104311204001002041000
61040322343330005200
732553011130230643
oct3155771051541000
9484440102051520
10113111330112000
113304a2780508a0
1210829897716800
134b16477a4a17c
141dd0890939a5a
15d12442bdb500
hex66dfc8a6c200

113111330112000 has 1920 divisors, whose sum is σ = 457798978061568. Its totient is φ = 26601357312000.

The previous prime is 113111330111957. The next prime is 113111330112007. The reversal of 113111330112000 is 211033111311.

113111330112000 is a `hidden beast` number, since 1 + 1 + 311 + 1 + 330 + 1 + 1 + 20 + 0 + 0 = 666.

It is a tau number, because it is divible by the number of its divisors (1920).

It is a Harshad number since it is a multiple of its sum of digits (18).

It is not an unprimeable number, because it can be changed into a prime (113111330112007) by changing a digit.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 131985215572 + ... + 131985216428.

Almost surely, 2113111330112000 is an apocalyptic number.

113111330112000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 113111330112000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (228899489030784).

113111330112000 is an abundant number, since it is smaller than the sum of its proper divisors (344687647949568).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113111330112000 is a wasteful number, since it uses less digits than its factorization.

113111330112000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1507 (or 1478 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 18.

Adding to 113111330112000 its reverse (211033111311), we get a palindrome (113322363223311).

The spelling of 113111330112000 in words is "one hundred thirteen trillion, one hundred eleven billion, three hundred thirty million, one hundred twelve thousand".