Base | Representation |
---|---|
bin | 1010010010011001010100… |
… | …1101011010010010100111 |
3 | 1111001100001122102201200111 |
4 | 2210212111031122102213 |
5 | 2440310214431223421 |
6 | 40020134355153451 |
7 | 2245126616301004 |
oct | 244462515322247 |
9 | 44040048381614 |
10 | 11311152211111 |
11 | 367103a5a6505 |
12 | 1328215ba5887 |
13 | 64083887173c |
14 | 2b166988a8ab |
15 | 149367e71ee1 |
hex | a499535a4a7 |
11311152211111 has 2 divisors, whose sum is σ = 11311152211112. Its totient is φ = 11311152211110.
The previous prime is 11311152211109. The next prime is 11311152211171. The reversal of 11311152211111 is 11111225111311.
It is a m-pointer prime, because the next prime (11311152211171) can be obtained adding 11311152211111 to its product of digits (60).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11311152211111 - 21 = 11311152211109 is a prime.
Together with 11311152211109, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11311152211171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655576105555 + 5655576105556.
It is an arithmetic number, because the mean of its divisors is an integer number (5655576105556).
Almost surely, 211311152211111 is an apocalyptic number.
11311152211111 is a deficient number, since it is larger than the sum of its proper divisors (1).
11311152211111 is an equidigital number, since it uses as much as digits as its factorization.
11311152211111 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 60, while the sum is 22.
Adding to 11311152211111 its reverse (11111225111311), we get a palindrome (22422377322422).
The spelling of 11311152211111 in words is "eleven trillion, three hundred eleven billion, one hundred fifty-two million, two hundred eleven thousand, one hundred eleven".
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