1131121220113 has 2 divisors, whose sum is σ = 1131121220114. Its totient is φ = 1131121220112.

The previous prime is 1131121220093. The next prime is 1131121220123. The reversal of 1131121220113 is 3110221211311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1008853509889 + 122267710224 = 1004417^2 + 349668^2 .

It is an emirp because it is prime and its reverse (3110221211311) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1131121220113 is a prime.

It is not a weakly prime, because it can be changed into another prime (1131121220123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565560610056 + 565560610057.

It is an arithmetic number, because the mean of its divisors is an integer number (565560610057).

Almost surely, 2^{1131121220113} is an apocalyptic number.

It is an amenable number.

1131121220113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131121220113 is an equidigital number, since it uses as much as digits as its factorization.

1131121220113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 19.

Adding to 1131121220113 its reverse (3110221211311), we get a palindrome (4241342431424).

The spelling of 1131121220113 in words is "one trillion, one hundred thirty-one billion, one hundred twenty-one million, two hundred twenty thousand, one hundred thirteen".