1131121220123 has 2 divisors, whose sum is σ = 1131121220124. Its totient is φ = 1131121220122.

The previous prime is 1131121220113. The next prime is 1131121220149. The reversal of 1131121220123 is 3210221211311.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1131121220123 - 2⁶ = 1131121220059 is a prime.

It is a super-2 number, since 2×1131121220123² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1131121220095 and 1131121220104.

It is not a weakly prime, because it can be changed into another prime (1131121220113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565560610061 + 565560610062.

It is an arithmetic number, because the mean of its divisors is an integer number (565560610062).

Almost surely, 2^{1131121220123} is an apocalyptic number.

1131121220123 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131121220123 is an equidigital number, since it uses as much as digits as its factorization.

1131121220123 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 1131121220123 its reverse (3210221211311), we get a palindrome (4341342431434).

The spelling of 1131121220123 in words is "one trillion, one hundred thirty-one billion, one hundred twenty-one million, two hundred twenty thousand, one hundred twenty-three".