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11311213001 = 111028292091
BaseRepresentation
bin10101000100011001…
…10110100111001001
31002012022001011012212
422202030312213021
5141131132304001
65110222314505
7550205503244
oct124214664711
932168034185
1011311213001
114884980820
122238128a35
1310b355015a
1479436225b
154630657bb
hex2a23369c9

11311213001 has 4 divisors (see below), whose sum is σ = 12339505104. Its totient is φ = 10282920900.

The previous prime is 11311212977. The next prime is 11311213013. The reversal of 11311213001 is 10031211311.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10031211311 = 11911928301.

It is a cyclic number.

It is not a de Polignac number, because 11311213001 - 26 = 11311212937 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11311216001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 514146035 + ... + 514146056.

It is an arithmetic number, because the mean of its divisors is an integer number (3084876276).

Almost surely, 211311213001 is an apocalyptic number.

11311213001 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

11311213001 is a deficient number, since it is larger than the sum of its proper divisors (1028292103).

11311213001 is a wasteful number, since it uses less digits than its factorization.

11311213001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1028292102.

The product of its (nonzero) digits is 18, while the sum is 14.

Adding to 11311213001 its reverse (10031211311), we get a palindrome (21342424312).

The spelling of 11311213001 in words is "eleven billion, three hundred eleven million, two hundred thirteen thousand, one".

Divisors: 1 11 1028292091 11311213001