Base | Representation |
---|---|
bin | 110100101011000000… |
… | …0100010111010110111 |
3 | 101210221222102201200111 |
4 | 1221112000202322313 |
5 | 3323123201231203 |
6 | 123544001323451 |
7 | 11113011161251 |
oct | 1512600427267 |
9 | 353858381614 |
10 | 113112133303 |
11 | 43a74939a04 |
12 | 19b09036587 |
13 | a8881b27c0 |
14 | 5690658cd1 |
15 | 2e2043b26d |
hex | 1a56022eb7 |
113112133303 has 8 divisors (see below), whose sum is σ = 121818171888. Its totient is φ = 104406824064.
The previous prime is 113112133301. The next prime is 113112133307. The reversal of 113112133303 is 303331211311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 113112133303 - 21 = 113112133301 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113112133301) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 164175 + ... + 503167.
It is an arithmetic number, because the mean of its divisors is an integer number (15227271486).
Almost surely, 2113112133303 is an apocalyptic number.
113112133303 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
113112133303 is a deficient number, since it is larger than the sum of its proper divisors (8706038585).
113112133303 is a wasteful number, since it uses less digits than its factorization.
113112133303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 364673.
The product of its (nonzero) digits is 486, while the sum is 22.
Adding to 113112133303 its reverse (303331211311), we get a palindrome (416443344614).
The spelling of 113112133303 in words is "one hundred thirteen billion, one hundred twelve million, one hundred thirty-three thousand, three hundred three".
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