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11311220013 = 337101902883
BaseRepresentation
bin10101000100011001…
…11000010100101101
31002012022001111211120
422202030320110231
5141131133020023
65110222411153
7550205532552
oct124214702455
932168044746
1011311220013
114884986015
122238130ab9
1310b35533c2
14794364a29
154630678e3
hex2a233852d

11311220013 has 8 divisors (see below), whose sum is σ = 15489238368. Its totient is φ = 7337007504.

The previous prime is 11311219991. The next prime is 11311220033. The reversal of 11311220013 is 31002211311.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 11311220013 - 218 = 11310957869 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11311219974 and 11311220001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11311220033) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 50951331 + ... + 50951552.

It is an arithmetic number, because the mean of its divisors is an integer number (1936154796).

Almost surely, 211311220013 is an apocalyptic number.

It is an amenable number.

11311220013 is a deficient number, since it is larger than the sum of its proper divisors (4178018355).

11311220013 is a wasteful number, since it uses less digits than its factorization.

11311220013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 101902923.

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 11311220013 its reverse (31002211311), we get a palindrome (42313431324).

The spelling of 11311220013 in words is "eleven billion, three hundred eleven million, two hundred twenty thousand, thirteen".

Divisors: 1 3 37 111 101902883 305708649 3770406671 11311220013