11311234535 has 4 divisors (see below), whose sum is σ = 13573481448. Its totient is φ = 9048987624.

The previous prime is 11311234511. The next prime is 11311234541. The reversal of 11311234535 is 53543211311.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 53543211311 = 1213 ⋅44141147.

It is a cyclic number.

It is not a de Polignac number, because 11311234535 - 2⁶ = 11311234471 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11311234498 and 11311234507.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1131123449 + ... + 1131123458.

It is an arithmetic number, because the mean of its divisors is an integer number (3393370362).

Almost surely, 2^11311234535 is an apocalyptic number.

11311234535 is a deficient number, since it is larger than the sum of its proper divisors (2262246913).

11311234535 is an equidigital number, since it uses as much as digits as its factorization.

11311234535 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2262246912.

The product of its digits is 5400, while the sum is 29.

Adding to 11311234535 its reverse (53543211311), we get a palindrome (64854445846).

The spelling of 11311234535 in words is "eleven billion, three hundred eleven million, two hundred thirty-four thousand, five hundred thirty-five".