Base | Representation |
---|---|
bin | 110100101011000010… |
… | …0001110111111000111 |
3 | 101210222001020212001122 |
4 | 1221112010032333013 |
5 | 3323123423201411 |
6 | 123544034144155 |
7 | 11113022326265 |
oct | 1512604167707 |
9 | 353861225048 |
10 | 113113100231 |
11 | 43a7543a41a |
12 | 19b0942205b |
13 | a888460951 |
14 | 569082b435 |
15 | 2e2057c9db |
hex | 1a5610efc7 |
113113100231 has 4 divisors (see below), whose sum is σ = 114114101232. Its totient is φ = 112112099232.
The previous prime is 113113100227. The next prime is 113113100239. The reversal of 113113100231 is 132001311311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 113113100231 - 22 = 113113100227 is a prime.
It is a super-2 number, since 2×1131131002312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113113100239) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 500500331 + ... + 500500556.
It is an arithmetic number, because the mean of its divisors is an integer number (28528525308).
Almost surely, 2113113100231 is an apocalyptic number.
113113100231 is a deficient number, since it is larger than the sum of its proper divisors (1001001001).
113113100231 is a wasteful number, since it uses less digits than its factorization.
113113100231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1001001000.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 113113100231 its reverse (132001311311), we get a palindrome (245114411542).
The spelling of 113113100231 in words is "one hundred thirteen billion, one hundred thirteen million, one hundred thousand, two hundred thirty-one".
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