Base | Representation |
---|---|
bin | 10101000100011010… |
… | …01110100111000110 |
3 | 1002012022020011001122 |
4 | 22202031032213012 |
5 | 141131143430202 |
6 | 5110224353542 |
7 | 550206362654 |
oct | 124215164706 |
9 | 32168204048 |
10 | 11311311302 |
11 | 4884a38665 |
12 | 22381758b2 |
13 | 10b3585b15 |
14 | 794389dd4 |
15 | 4630849a2 |
hex | 2a234e9c6 |
11311311302 has 4 divisors (see below), whose sum is σ = 16966966956. Its totient is φ = 5655655650.
The previous prime is 11311311299. The next prime is 11311311367. The reversal of 11311311302 is 20311311311.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 20311311311 = 43 ⋅472356077.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2827827824 + ... + 2827827827.
It is an arithmetic number, because the mean of its divisors is an integer number (4241741739).
Almost surely, 211311311302 is an apocalyptic number.
11311311302 is a deficient number, since it is larger than the sum of its proper divisors (5655655654).
11311311302 is an equidigital number, since it uses as much as digits as its factorization.
11311311302 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5655655653.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 11311311302 its reverse (20311311311), we get a palindrome (31622622613).
Subtracting 11311311302 from its reverse (20311311311), we obtain a palindrome (9000000009).
The spelling of 11311311302 in words is "eleven billion, three hundred eleven million, three hundred eleven thousand, three hundred two".
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