Base | Representation |
---|---|
bin | 1010010010011001111010… |
… | …1100010010110110011111 |
3 | 1111001100110201210101102101 |
4 | 2210212132230102312133 |
5 | 2440311031143131142 |
6 | 40020202241105531 |
7 | 2245133560452661 |
oct | 244463654226637 |
9 | 44040421711371 |
10 | 11311311302047 |
11 | 3671111387919 |
12 | 132825b3282a7 |
13 | 6408628044a3 |
14 | 2b1682a60531 |
15 | 149376dea0b7 |
hex | a499eb12d9f |
11311311302047 has 2 divisors, whose sum is σ = 11311311302048. Its totient is φ = 11311311302046.
The previous prime is 11311311301981. The next prime is 11311311302051. The reversal of 11311311302047 is 74020311311311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11311311302047 - 219 = 11311310777759 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11311311312047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655655651023 + 5655655651024.
It is an arithmetic number, because the mean of its divisors is an integer number (5655655651024).
Almost surely, 211311311302047 is an apocalyptic number.
11311311302047 is a deficient number, since it is larger than the sum of its proper divisors (1).
11311311302047 is an equidigital number, since it uses as much as digits as its factorization.
11311311302047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 28.
Adding to 11311311302047 its reverse (74020311311311), we get a palindrome (85331622613358).
The spelling of 11311311302047 in words is "eleven trillion, three hundred eleven billion, three hundred eleven million, three hundred two thousand, forty-seven".
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