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11311311301981 is a prime number
BaseRepresentation
bin1010010010011001111010…
…1100010010110101011101
31111001100110201210101022221
42210212132230102311131
52440311031143130411
640020202241105341
72245133560452535
oct244463654226535
944040421711287
1011311311301981
113671111387869
12132825b328251
13640862804452
142b1682a604c5
15149376dea071
hexa499eb12d5d

11311311301981 has 2 divisors, whose sum is σ = 11311311301982. Its totient is φ = 11311311301980.

The previous prime is 11311311301973. The next prime is 11311311302047. The reversal of 11311311301981 is 18910311311311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11301463915225 + 9847386756 = 3361765^2 + 99234^2 .

It is a cyclic number.

It is not a de Polignac number, because 11311311301981 - 23 = 11311311301973 is a prime.

It is a super-2 number, since 2×113113113019812 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11311311304981) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655655650990 + 5655655650991.

It is an arithmetic number, because the mean of its divisors is an integer number (5655655650991).

Almost surely, 211311311301981 is an apocalyptic number.

It is an amenable number.

11311311301981 is a deficient number, since it is larger than the sum of its proper divisors (1).

11311311301981 is an equidigital number, since it uses as much as digits as its factorization.

11311311301981 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1944, while the sum is 34.

The spelling of 11311311301981 in words is "eleven trillion, three hundred eleven billion, three hundred eleven million, three hundred one thousand, nine hundred eighty-one".