Base | Representation |
---|---|
bin | 1010010010011001111010… |
… | …1100011000000010100111 |
3 | 1111001100110201211110120122 |
4 | 2210212132230120002213 |
5 | 2440311031144321203 |
6 | 40020202241352155 |
7 | 2245133560601645 |
oct | 244463654300247 |
9 | 44040421743518 |
10 | 11311311323303 |
11 | 36711113a1892 |
12 | 132825b33865b |
13 | 640862811074 |
14 | 2b1682a68195 |
15 | 149376e01538 |
hex | a499eb180a7 |
11311311323303 has 2 divisors, whose sum is σ = 11311311323304. Its totient is φ = 11311311323302.
The previous prime is 11311311323281. The next prime is 11311311323329. The reversal of 11311311323303 is 30332311311311.
It is an a-pointer prime, because the next prime (11311311323329) can be obtained adding 11311311323303 to its sum of digits (26).
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11311311323303 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11311311323903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655655661651 + 5655655661652.
It is an arithmetic number, because the mean of its divisors is an integer number (5655655661652).
Almost surely, 211311311323303 is an apocalyptic number.
11311311323303 is a deficient number, since it is larger than the sum of its proper divisors (1).
11311311323303 is an equidigital number, since it uses as much as digits as its factorization.
11311311323303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1458, while the sum is 26.
Adding to 11311311323303 its reverse (30332311311311), we get a palindrome (41643622634614).
The spelling of 11311311323303 in words is "eleven trillion, three hundred eleven billion, three hundred eleven million, three hundred twenty-three thousand, three hundred three".
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