113113120014041 has 8 divisors (see below), whose sum is σ = 129272208758784. Its totient is φ = 96954049169280.

The previous prime is 113113120014031. The next prime is 113113120014157. The reversal of 113113120014041 is 140410021311311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-113113120014041 is a prime.

It is a super-3 number, since 3×113113120014041³ (a number of 43 digits) contains 333 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 113113120013998 and 113113120014016.

It is not an unprimeable number, because it can be changed into a prime (113113120014031) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 14339816 + ... + 20781158.

It is an arithmetic number, because the mean of its divisors is an integer number (16159026094848).

Almost surely, 2^{113113120014041} is an apocalyptic number.

It is an amenable number.

113113120014041 is a deficient number, since it is larger than the sum of its proper divisors (16159088744743).

113113120014041 is an equidigital number, since it uses as much as digits as its factorization.

113113120014041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8949991.

The product of its (nonzero) digits is 288, while the sum is 23.

Adding to 113113120014041 its reverse (140410021311311), we get a palindrome (253523141325352).

The spelling of 113113120014041 in words is "one hundred thirteen trillion, one hundred thirteen billion, one hundred twenty million, fourteen thousand, forty-one".