Base | Representation |
---|---|
bin | 10101000100011010… |
… | …10000110010010101 |
3 | 1002012022020121021200 |
4 | 22202031100302111 |
5 | 141131144221323 |
6 | 5110224503113 |
7 | 550206430644 |
oct | 124215206225 |
9 | 32168217250 |
10 | 11311320213 |
11 | 4884a44326 |
12 | 223817aa99 |
13 | 10b3589bab |
14 | 79438d35b |
15 | 463087443 |
hex | 2a2350c95 |
11311320213 has 12 divisors (see below), whose sum is σ = 17048946720. Its totient is φ = 7213015656.
The previous prime is 11311320187. The next prime is 11311320233. The reversal of 11311320213 is 31202311311.
11311320213 is a `hidden beast` number, since 1 + 131 + 1 + 320 + 213 = 666.
It is not a de Polignac number, because 11311320213 - 26 = 11311320149 is a prime.
It is a super-3 number, since 3×113113202133 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11311320233) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 27321823 + ... + 27322236.
It is an arithmetic number, because the mean of its divisors is an integer number (1420745560).
Almost surely, 211311320213 is an apocalyptic number.
It is an amenable number.
11311320213 is a deficient number, since it is larger than the sum of its proper divisors (5737626507).
11311320213 is a wasteful number, since it uses less digits than its factorization.
11311320213 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 54644088 (or 54644085 counting only the distinct ones).
The product of its (nonzero) digits is 108, while the sum is 18.
Adding to 11311320213 its reverse (31202311311), we get a palindrome (42513631524).
The spelling of 11311320213 in words is "eleven billion, three hundred eleven million, three hundred twenty thousand, two hundred thirteen".
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