Base | Representation |
---|---|
bin | 10101000100011010… |
… | …10000110100000011 |
3 | 1002012022020121102202 |
4 | 22202031100310003 |
5 | 141131144222243 |
6 | 5110224503415 |
7 | 550206431162 |
oct | 124215206403 |
9 | 32168217382 |
10 | 11311320323 |
11 | 4884a44416 |
12 | 223817ab6b |
13 | 10b3589c64 |
14 | 79438d3d9 |
15 | 4630874b8 |
hex | 2a2350d03 |
11311320323 has 4 divisors (see below), whose sum is σ = 11574374328. Its totient is φ = 11048266320.
The previous prime is 11311320257. The next prime is 11311320337. The reversal of 11311320323 is 32302311311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11311320323 - 28 = 11311320067 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11311320295 and 11311320304.
It is not an unprimeable number, because it can be changed into a prime (11311320353) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 131526938 + ... + 131527023.
It is an arithmetic number, because the mean of its divisors is an integer number (2893593582).
Almost surely, 211311320323 is an apocalyptic number.
11311320323 is a deficient number, since it is larger than the sum of its proper divisors (263054005).
11311320323 is an equidigital number, since it uses as much as digits as its factorization.
11311320323 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 263054004.
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 11311320323 its reverse (32302311311), we get a palindrome (43613631634).
The spelling of 11311320323 in words is "eleven billion, three hundred eleven million, three hundred twenty thousand, three hundred twenty-three".
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