Base | Representation |
---|---|
bin | 1010010010011001111111… |
… | …1011101000101110011111 |
3 | 1111001100112011221002020211 |
4 | 2210212133323220232133 |
5 | 2440311102004213043 |
6 | 40020204302553251 |
7 | 2245134232320253 |
oct | 244463773505637 |
9 | 44040464832224 |
10 | 11311332101023 |
11 | 36711220a3459 |
12 | 1328266298827 |
13 | 640866c07486 |
14 | 2b1685716263 |
15 | 149378b57a9d |
hex | a499fee8b9f |
11311332101023 has 2 divisors, whose sum is σ = 11311332101024. Its totient is φ = 11311332101022.
The previous prime is 11311332100997. The next prime is 11311332101071. The reversal of 11311332101023 is 32010123311311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11311332101023 - 225 = 11311298546591 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11311332100985 and 11311332101003.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11311332101423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655666050511 + 5655666050512.
It is an arithmetic number, because the mean of its divisors is an integer number (5655666050512).
Almost surely, 211311332101023 is an apocalyptic number.
11311332101023 is a deficient number, since it is larger than the sum of its proper divisors (1).
11311332101023 is an equidigital number, since it uses as much as digits as its factorization.
11311332101023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 324, while the sum is 22.
Adding to 11311332101023 its reverse (32010123311311), we get a palindrome (43321455412334).
The spelling of 11311332101023 in words is "eleven trillion, three hundred eleven billion, three hundred thirty-two million, one hundred one thousand, twenty-three".
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