11311452133 has 4 divisors (see below), whose sum is σ = 11311666720. Its totient is φ = 11311237548.

The previous prime is 11311452121. The next prime is 11311452137. The reversal of 11311452133 is 33125411311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33125411311 = 389 ⋅85155299.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11311452133 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11311452098 and 11311452107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11311452137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32416 + ... + 153862.

It is an arithmetic number, because the mean of its divisors is an integer number (2827916680).

Almost surely, 2^11311452133 is an apocalyptic number.

It is an amenable number.

11311452133 is a deficient number, since it is larger than the sum of its proper divisors (214587).

11311452133 is an equidigital number, since it uses as much as digits as its factorization.

11311452133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 214586.

The product of its digits is 1080, while the sum is 25.

Adding to 11311452133 its reverse (33125411311), we get a palindrome (44436863444).

The spelling of 11311452133 in words is "eleven billion, three hundred eleven million, four hundred fifty-two thousand, one hundred thirty-three".