Base | Representation |
---|---|
bin | 110100101011001101… |
… | …1100011011011110111 |
3 | 101210222110202102121201 |
4 | 1221112123203123313 |
5 | 3323132004311203 |
6 | 123544413153331 |
7 | 11113125306535 |
oct | 1512633433367 |
9 | 353873672551 |
10 | 113119213303 |
11 | 43a78935248 |
12 | 19b0b48b847 |
13 | a8897c1255 |
14 | 569157d155 |
15 | 2e20d88e1d |
hex | 1a566e36f7 |
113119213303 has 2 divisors, whose sum is σ = 113119213304. Its totient is φ = 113119213302.
The previous prime is 113119213231. The next prime is 113119213321. The reversal of 113119213303 is 303312911311.
It is a strong prime.
It is an emirp because it is prime and its reverse (303312911311) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-113119213303 is a prime.
It is a super-2 number, since 2×1131192133032 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113119216303) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56559606651 + 56559606652.
It is an arithmetic number, because the mean of its divisors is an integer number (56559606652).
Almost surely, 2113119213303 is an apocalyptic number.
113119213303 is a deficient number, since it is larger than the sum of its proper divisors (1).
113119213303 is an equidigital number, since it uses as much as digits as its factorization.
113119213303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1458, while the sum is 28.
The spelling of 113119213303 in words is "one hundred thirteen billion, one hundred nineteen million, two hundred thirteen thousand, three hundred three".
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