Base | Representation |
---|---|
bin | 10101000100011111… |
… | …10110110000010111 |
3 | 1002012100112010210211 |
4 | 22202033312300113 |
5 | 141131333000043 |
6 | 5110251230251 |
7 | 550215261622 |
oct | 124217666027 |
9 | 32170463724 |
10 | 11312000023 |
11 | 4885369055 |
12 | 2238448387 |
13 | 10b376744c |
14 | 7944c8db9 |
15 | 46316da9d |
hex | 2a23f6c17 |
11312000023 has 2 divisors, whose sum is σ = 11312000024. Its totient is φ = 11312000022.
The previous prime is 11311999969. The next prime is 11312000069. The reversal of 11312000023 is 32000021311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11312000023 - 229 = 10775129111 is a prime.
It is a super-2 number, since 2×113120000232 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11311999967 and 11312000012.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11312000083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656000011 + 5656000012.
It is an arithmetic number, because the mean of its divisors is an integer number (5656000012).
Almost surely, 211312000023 is an apocalyptic number.
11312000023 is a deficient number, since it is larger than the sum of its proper divisors (1).
11312000023 is an equidigital number, since it uses as much as digits as its factorization.
11312000023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36, while the sum is 13.
Adding to 11312000023 its reverse (32000021311), we get a palindrome (43312021334).
The spelling of 11312000023 in words is "eleven billion, three hundred twelve million, twenty-three", and thus it is an aban number.
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