Base | Representation |
---|---|
bin | 10101000100011111… |
… | …10110110110010011 |
3 | 1002012100112011022220 |
4 | 22202033312312103 |
5 | 141131333003103 |
6 | 5110251232123 |
7 | 550215263004 |
oct | 124217666623 |
9 | 32170464286 |
10 | 11312000403 |
11 | 4885369370 |
12 | 2238448643 |
13 | 10b3767682 |
14 | 7944c91ab |
15 | 46316dc53 |
hex | 2a23f6d93 |
11312000403 has 32 divisors (see below), whose sum is σ = 16565796864. Its totient is φ = 6809220000.
The previous prime is 11312000387. The next prime is 11312000437. The reversal of 11312000403 is 30400021311.
It is not a de Polignac number, because 11312000403 - 24 = 11312000387 is a prime.
It is a super-2 number, since 2×113120004032 (a number of 21 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (11312000443) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 6245368 + ... + 6247178.
It is an arithmetic number, because the mean of its divisors is an integer number (517681152).
Almost surely, 211312000403 is an apocalyptic number.
11312000403 is a deficient number, since it is larger than the sum of its proper divisors (5253796461).
11312000403 is a wasteful number, since it uses less digits than its factorization.
11312000403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3007.
The product of its (nonzero) digits is 72, while the sum is 15.
Adding to 11312000403 its reverse (30400021311), we get a palindrome (41712021714).
The spelling of 11312000403 in words is "eleven billion, three hundred twelve million, four hundred three", and thus it is an aban number.
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