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11312000403 = 3111919911811
BaseRepresentation
bin10101000100011111…
…10110110110010011
31002012100112011022220
422202033312312103
5141131333003103
65110251232123
7550215263004
oct124217666623
932170464286
1011312000403
114885369370
122238448643
1310b3767682
147944c91ab
1546316dc53
hex2a23f6d93

11312000403 has 32 divisors (see below), whose sum is σ = 16565796864. Its totient is φ = 6809220000.

The previous prime is 11312000387. The next prime is 11312000437. The reversal of 11312000403 is 30400021311.

It is not a de Polignac number, because 11312000403 - 24 = 11312000387 is a prime.

It is a super-2 number, since 2×113120004032 (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (11312000443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 6245368 + ... + 6247178.

It is an arithmetic number, because the mean of its divisors is an integer number (517681152).

Almost surely, 211312000403 is an apocalyptic number.

11312000403 is a deficient number, since it is larger than the sum of its proper divisors (5253796461).

11312000403 is a wasteful number, since it uses less digits than its factorization.

11312000403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3007.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 11312000403 its reverse (30400021311), we get a palindrome (41712021714).

The spelling of 11312000403 in words is "eleven billion, three hundred twelve million, four hundred three", and thus it is an aban number.

Divisors: 1 3 11 33 191 573 991 1811 2101 2973 5433 6303 10901 19921 32703 59763 189281 345901 567843 1037703 1794701 2082091 3804911 5384103 6246273 11414733 19741711 59225133 342787891 1028363673 3770666801 11312000403