| Base | Representation |
|---|---|
| bin | 1010010010011100011111… |
| … | …0011010100101010011100 |
| 3 | 1111001102020210121012022200 |
| 4 | 2210213013303110222130 |
| 5 | 2440313434224312312 |
| 6 | 40020354520011500 |
| 7 | 2245156634051211 |
| oct | 244470763245234 |
| 9 | 44042223535280 |
| 10 | 11312001010332 |
| 11 | 3671435737970 |
| 12 | 1328412300b90 |
| 13 | 64094267c2b9 |
| 14 | 2b170a4b9b08 |
| 15 | 1493b77380dc |
| hex | a49c7cd4a9c |
11312001010332 has 1152 divisors, whose sum is σ = 36139364352000. Its totient is φ = 2942027827200.
The previous prime is 11312001010327. The next prime is 11312001010339. The reversal of 11312001010332 is 23301010021311.
11312001010332 is a `hidden beast` number, since 1 + 1 + 31 + 200 + 101 + 0 + 332 = 666.
11312001010332 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-3 number, since 3×113120010103323 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11312001010339) by changing a digit.
It is a polite number, since it can be written in 383 ways as a sum of consecutive naturals, for example, 67736532913 + ... + 67736533079.
It is an arithmetic number, because the mean of its divisors is an integer number (31370976000).
Almost surely, 211312001010332 is an apocalyptic number.
11312001010332 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 11312001010332, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (18069682176000).
11312001010332 is an abundant number, since it is smaller than the sum of its proper divisors (24827363341668).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11312001010332 is a wasteful number, since it uses less digits than its factorization.
11312001010332 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 487 (or 482 counting only the distinct ones).
The product of its (nonzero) digits is 108, while the sum is 18.
Adding to 11312001010332 its reverse (23301010021311), we get a palindrome (34613011031643).
The spelling of 11312001010332 in words is "eleven trillion, three hundred twelve billion, one million, ten thousand, three hundred thirty-two".
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