Base | Representation |
---|---|
bin | 110100101011001111… |
… | …0100110001111001100 |
3 | 101210222112020222010220 |
4 | 1221112132212033030 |
5 | 3323132210324322 |
6 | 123544442231340 |
7 | 11113135142025 |
oct | 1512636461714 |
9 | 353875228126 |
10 | 113120011212 |
11 | 43a7932a77a |
12 | 19b0b7b5550 |
13 | a889a104a0 |
14 | 5691709c4c |
15 | 2e20e9555c |
hex | 1a567a63cc |
113120011212 has 48 divisors (see below), whose sum is σ = 286858128480. Its totient is φ = 34486829568.
The previous prime is 113120011153. The next prime is 113120011217. The reversal of 113120011212 is 212110021311.
It is a super-2 number, since 2×1131200112122 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 113120011191 and 113120011200.
It is not an unprimeable number, because it can be changed into a prime (113120011217) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3309273 + ... + 3343280.
It is an arithmetic number, because the mean of its divisors is an integer number (5976211010).
Almost surely, 2113120011212 is an apocalyptic number.
113120011212 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
113120011212 is an abundant number, since it is smaller than the sum of its proper divisors (173738117268).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113120011212 is a wasteful number, since it uses less digits than its factorization.
113120011212 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6652682 (or 6652680 counting only the distinct ones).
The product of its (nonzero) digits is 24, while the sum is 15.
Adding to 113120011212 its reverse (212110021311), we get a palindrome (325230032523).
The spelling of 113120011212 in words is "one hundred thirteen billion, one hundred twenty million, eleven thousand, two hundred twelve".
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