Base | Representation |
---|---|
bin | 110100101011001111… |
… | …0101110010101110011 |
3 | 101210222112022122200012 |
4 | 1221112132232111303 |
5 | 3323132212410103 |
6 | 123544443045135 |
7 | 11113135340552 |
oct | 1512636562563 |
9 | 353875278605 |
10 | 113120044403 |
11 | 43a79352703 |
12 | 19b0b8107ab |
13 | a889a22622 |
14 | 5691717d99 |
15 | 2e20ea02d8 |
hex | 1a567ae573 |
113120044403 has 8 divisors (see below), whose sum is σ = 119777292000. Its totient is φ = 106463144320.
The previous prime is 113120044361. The next prime is 113120044447. The reversal of 113120044403 is 304440021311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 113120044403 - 212 = 113120040307 is a prime.
It is a super-2 number, since 2×1131200444032 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (113120044003) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 910613 + ... + 1027353.
It is an arithmetic number, because the mean of its divisors is an integer number (14972161500).
Almost surely, 2113120044403 is an apocalyptic number.
113120044403 is a deficient number, since it is larger than the sum of its proper divisors (6657247597).
113120044403 is a wasteful number, since it uses less digits than its factorization.
113120044403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 173757.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 113120044403 its reverse (304440021311), we get a palindrome (417560065714).
The spelling of 113120044403 in words is "one hundred thirteen billion, one hundred twenty million, forty-four thousand, four hundred three".
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