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113120044403 = 1756999116741
BaseRepresentation
bin110100101011001111…
…0101110010101110011
3101210222112022122200012
41221112132232111303
53323132212410103
6123544443045135
711113135340552
oct1512636562563
9353875278605
10113120044403
1143a79352703
1219b0b8107ab
13a889a22622
145691717d99
152e20ea02d8
hex1a567ae573

113120044403 has 8 divisors (see below), whose sum is σ = 119777292000. Its totient is φ = 106463144320.

The previous prime is 113120044361. The next prime is 113120044447. The reversal of 113120044403 is 304440021311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 113120044403 - 212 = 113120040307 is a prime.

It is a super-2 number, since 2×1131200444032 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (113120044003) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 910613 + ... + 1027353.

It is an arithmetic number, because the mean of its divisors is an integer number (14972161500).

Almost surely, 2113120044403 is an apocalyptic number.

113120044403 is a deficient number, since it is larger than the sum of its proper divisors (6657247597).

113120044403 is a wasteful number, since it uses less digits than its factorization.

113120044403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 173757.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 113120044403 its reverse (304440021311), we get a palindrome (417560065714).

The spelling of 113120044403 in words is "one hundred thirteen billion, one hundred twenty million, forty-four thousand, four hundred three".

Divisors: 1 17 56999 116741 968983 1984597 6654120259 113120044403