Search a number
-
+
1131202001141 is a prime number
BaseRepresentation
bin10000011101100000111…
…001001011100011110101
311000010211102010122200122
4100131200321023203311
5122013200203014031
62223400024421325
7144504145234622
oct20354071134365
94003742118618
101131202001141
113a68160482a3
12163299317845
13828971b5644
143ca71403349
151e659dad47b
hex10760e4b8f5

1131202001141 has 2 divisors, whose sum is σ = 1131202001142. Its totient is φ = 1131202001140.

The previous prime is 1131202001129. The next prime is 1131202001219. The reversal of 1131202001141 is 1411002021311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 722081860516 + 409120140625 = 849754^2 + 639625^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1131202001141 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1131202901141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565601000570 + 565601000571.

It is an arithmetic number, because the mean of its divisors is an integer number (565601000571).

Almost surely, 21131202001141 is an apocalyptic number.

It is an amenable number.

1131202001141 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131202001141 is an equidigital number, since it uses as much as digits as its factorization.

1131202001141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 1131202001141 its reverse (1411002021311), we get a palindrome (2542204022452).

The spelling of 1131202001141 in words is "one trillion, one hundred thirty-one billion, two hundred two million, one thousand, one hundred forty-one".