Base | Representation |
---|---|
bin | 10000011101100000111… |
… | …001101000100100100101 |
3 | 11000010211102100200200211 |
4 | 100131200321220210211 |
5 | 122013200220314343 |
6 | 2223400031135421 |
7 | 144504146241232 |
oct | 20354071504445 |
9 | 4003742320624 |
10 | 1131202119973 |
11 | 3a6816119602 |
12 | 163299374571 |
13 | 82897227763 |
14 | 3ca71434789 |
15 | 1e659dd379d |
hex | 10760e68925 |
1131202119973 has 2 divisors, whose sum is σ = 1131202119974. Its totient is φ = 1131202119972.
The previous prime is 1131202119947. The next prime is 1131202120159. The reversal of 1131202119973 is 3799112021311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 655520168164 + 475681951809 = 809642^2 + 689697^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1131202119973 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1131202819973) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565601059986 + 565601059987.
It is an arithmetic number, because the mean of its divisors is an integer number (565601059987).
Almost surely, 21131202119973 is an apocalyptic number.
It is an amenable number.
1131202119973 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131202119973 is an equidigital number, since it uses as much as digits as its factorization.
1131202119973 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20412, while the sum is 40.
The spelling of 1131202119973 in words is "one trillion, one hundred thirty-one billion, two hundred two million, one hundred nineteen thousand, nine hundred seventy-three".
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