Base | Representation |
---|---|
bin | 10000011101100001000… |
… | …010010101001110000011 |
3 | 11000010211120122112022101 |
4 | 100131201002111032003 |
5 | 122013201311300003 |
6 | 2223400152051231 |
7 | 144504204515446 |
oct | 20354102251603 |
9 | 4003746575271 |
10 | 1131204400003 |
11 | 3a6817436627 |
12 | 16329a093b17 |
13 | 828978454a2 |
14 | 3ca7186965d |
15 | 1e65a1d411d |
hex | 10761095383 |
1131204400003 has 4 divisors (see below), whose sum is σ = 1131514918168. Its totient is φ = 1130893881840.
The previous prime is 1131204399973. The next prime is 1131204400021. The reversal of 1131204400003 is 3000044021311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1131204400003 - 229 = 1130667529091 is a prime.
It is a super-2 number, since 2×11312044000032 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1131204409003) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 155253618 + ... + 155260903.
It is an arithmetic number, because the mean of its divisors is an integer number (282878729542).
Almost surely, 21131204400003 is an apocalyptic number.
1131204400003 is a deficient number, since it is larger than the sum of its proper divisors (310518165).
1131204400003 is an equidigital number, since it uses as much as digits as its factorization.
1131204400003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 310518164.
The product of its (nonzero) digits is 288, while the sum is 19.
Adding to 1131204400003 its reverse (3000044021311), we get a palindrome (4131248421314).
The spelling of 1131204400003 in words is "one trillion, one hundred thirty-one billion, two hundred four million, four hundred thousand, three".
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