Base | Representation |
---|---|
bin | 10101000100100000… |
… | …01111011101100001 |
3 | 1002012100201021121202 |
4 | 22202100033131201 |
5 | 141131344214332 |
6 | 5110253330545 |
7 | 550216162634 |
oct | 124220173541 |
9 | 32170637552 |
10 | 11312101217 |
11 | 488542808a |
12 | 2238496a55 |
13 | 10b37a1521 |
14 | 794513c1b |
15 | 46318da62 |
hex | 2a240f761 |
11312101217 has 2 divisors, whose sum is σ = 11312101218. Its totient is φ = 11312101216.
The previous prime is 11312101183. The next prime is 11312101219. The reversal of 11312101217 is 71210121311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11244269521 + 67831696 = 106039^2 + 8236^2 .
It is a cyclic number.
It is not a de Polignac number, because 11312101217 - 222 = 11307906913 is a prime.
Together with 11312101219, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (11312101219) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656050608 + 5656050609.
It is an arithmetic number, because the mean of its divisors is an integer number (5656050609).
Almost surely, 211312101217 is an apocalyptic number.
It is an amenable number.
11312101217 is a deficient number, since it is larger than the sum of its proper divisors (1).
11312101217 is an equidigital number, since it uses as much as digits as its factorization.
11312101217 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 84, while the sum is 20.
Adding to 11312101217 its reverse (71210121311), we get a palindrome (82522222528).
The spelling of 11312101217 in words is "eleven billion, three hundred twelve million, one hundred one thousand, two hundred seventeen".
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