Base | Representation |
---|---|
bin | 10101000100100000… |
… | …01111011100111111 |
3 | 1002012100201021120111 |
4 | 22202100033130333 |
5 | 141131344214213 |
6 | 5110253330451 |
7 | 550216162555 |
oct | 124220173477 |
9 | 32170637514 |
10 | 11312101183 |
11 | 4885428059 |
12 | 2238496a27 |
13 | 10b37a14c6 |
14 | 794513bd5 |
15 | 46318da3d |
hex | 2a240f73f |
11312101183 has 2 divisors, whose sum is σ = 11312101184. Its totient is φ = 11312101182.
The previous prime is 11312101181. The next prime is 11312101217. The reversal of 11312101183 is 38110121311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11312101183 - 21 = 11312101181 is a prime.
Together with 11312101181, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11312101181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656050591 + 5656050592.
It is an arithmetic number, because the mean of its divisors is an integer number (5656050592).
Almost surely, 211312101183 is an apocalyptic number.
11312101183 is a deficient number, since it is larger than the sum of its proper divisors (1).
11312101183 is an equidigital number, since it uses as much as digits as its factorization.
11312101183 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 22.
Adding to 11312101183 its reverse (38110121311), we get a palindrome (49422222494).
The spelling of 11312101183 in words is "eleven billion, three hundred twelve million, one hundred one thousand, one hundred eighty-three".
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