Base | Representation |
---|---|
bin | 10101000100100000… |
… | …01111111001011001 |
3 | 1002012100201101001211 |
4 | 22202100033321121 |
5 | 141131344244001 |
6 | 5110253343121 |
7 | 550216201063 |
oct | 124220177131 |
9 | 32170641054 |
10 | 11312103001 |
11 | 4885429461 |
12 | 2238497aa1 |
13 | 10b37a2294 |
14 | 794514733 |
15 | 46318e351 |
hex | 2a240fe59 |
11312103001 has 2 divisors, whose sum is σ = 11312103002. Its totient is φ = 11312103000.
The previous prime is 11312102999. The next prime is 11312103007. The reversal of 11312103001 is 10030121311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10025015625 + 1287087376 = 100125^2 + 35876^2 .
It is a cyclic number.
It is not a de Polignac number, because 11312103001 - 21 = 11312102999 is a prime.
Together with 11312102999, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (11312103007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656051500 + 5656051501.
It is an arithmetic number, because the mean of its divisors is an integer number (5656051501).
Almost surely, 211312103001 is an apocalyptic number.
It is an amenable number.
11312103001 is a deficient number, since it is larger than the sum of its proper divisors (1).
11312103001 is an equidigital number, since it uses as much as digits as its factorization.
11312103001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18, while the sum is 13.
Adding to 11312103001 its reverse (10030121311), we get a palindrome (21342224312).
The spelling of 11312103001 in words is "eleven billion, three hundred twelve million, one hundred three thousand, one".
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