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1131210312110 = 25122611922601
BaseRepresentation
bin10000011101100001011…
…000111000100110101110
311000010211222202220012022
4100131201120320212232
5122013204314441420
62223400522510142
7144504306001064
oct20354130704656
94003758686168
101131210312110
113a681a80446a
121632a0065352
1382898b35488
143ca72568034
151e65a9a0c25
hex107616389ae

1131210312110 has 16 divisors (see below), whose sum is σ = 2036197375632. Its totient is φ = 452479944000.

The previous prime is 1131210312079. The next prime is 1131210312137. The reversal of 1131210312110 is 112130121311.

It is a super-2 number, since 2×11312103121102 (a number of 25 digits) contains 22 as substring.

It is a Curzon number.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 764810 + ... + 1687410.

It is an arithmetic number, because the mean of its divisors is an integer number (127262335977).

Almost surely, 21131210312110 is an apocalyptic number.

1131210312110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1131210312110 is a deficient number, since it is larger than the sum of its proper divisors (904987063522).

1131210312110 is a wasteful number, since it uses less digits than its factorization.

1131210312110 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1045219.

The product of its (nonzero) digits is 36, while the sum is 17.

Adding to 1131210312110 its reverse (112130121311), we get a palindrome (1243340433421).

The spelling of 1131210312110 in words is "one trillion, one hundred thirty-one billion, two hundred ten million, three hundred twelve thousand, one hundred ten".

Divisors: 1 2 5 10 122611 245222 613055 922601 1226110 1845202 4613005 9226010 113121031211 226242062422 565605156055 1131210312110