Base | Representation |
---|---|
bin | 1010010010011100111001… |
… | …0011011110001011100111 |
3 | 1111001102112101212120220001 |
4 | 2210213032103132023213 |
5 | 2440314200141214343 |
6 | 40020413414122131 |
7 | 2245162430235361 |
oct | 244471623361347 |
9 | 44042471776801 |
10 | 11312110101223 |
11 | 3671491278528 |
12 | 1328442950347 |
13 | 64095c156919 |
14 | 2b171ab95d31 |
15 | 1493c20d644d |
hex | a49ce4de2e7 |
11312110101223 has 4 divisors (see below), whose sum is σ = 11312168360760. Its totient is φ = 11312051841688.
The previous prime is 11312110101209. The next prime is 11312110101239. The reversal of 11312110101223 is 32210101121311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11312110101223 - 241 = 9113086845671 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 11312110101223.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11312110101263) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28837540 + ... + 29227177.
It is an arithmetic number, because the mean of its divisors is an integer number (2828042090190).
Almost surely, 211312110101223 is an apocalyptic number.
11312110101223 is a deficient number, since it is larger than the sum of its proper divisors (58259537).
11312110101223 is an equidigital number, since it uses as much as digits as its factorization.
11312110101223 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 58259536.
The product of its (nonzero) digits is 72, while the sum is 19.
Adding to 11312110101223 its reverse (32210101121311), we get a palindrome (43522211222534).
The spelling of 11312110101223 in words is "eleven trillion, three hundred twelve billion, one hundred ten million, one hundred one thousand, two hundred twenty-three".
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