Base | Representation |
---|---|
bin | 110100101011010001… |
… | …0110100111111111101 |
3 | 101210222121100022110111 |
4 | 1221112202310333331 |
5 | 3323133001322003 |
6 | 123544522110021 |
7 | 11113150441261 |
oct | 1512642647775 |
9 | 353877308414 |
10 | 113121120253 |
11 | 43a79a17a39 |
12 | 19b1004b311 |
13 | a88a00b21b |
14 | 56919180a1 |
15 | 2e21113e6d |
hex | 1a568b4ffd |
113121120253 has 2 divisors, whose sum is σ = 113121120254. Its totient is φ = 113121120252.
The previous prime is 113121120221. The next prime is 113121120311. The reversal of 113121120253 is 352021121311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 111822022404 + 1299097849 = 334398^2 + 36043^2 .
It is a cyclic number.
It is not a de Polignac number, because 113121120253 - 25 = 113121120221 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113121120653) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56560560126 + 56560560127.
It is an arithmetic number, because the mean of its divisors is an integer number (56560560127).
Almost surely, 2113121120253 is an apocalyptic number.
It is an amenable number.
113121120253 is a deficient number, since it is larger than the sum of its proper divisors (1).
113121120253 is an equidigital number, since it uses as much as digits as its factorization.
113121120253 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 360, while the sum is 22.
Adding to 113121120253 its reverse (352021121311), we get a palindrome (465142241564).
The spelling of 113121120253 in words is "one hundred thirteen billion, one hundred twenty-one million, one hundred twenty thousand, two hundred fifty-three".
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