Base | Representation |
---|---|
bin | 10000011101100001011… |
… | …100101101000010101001 |
3 | 11000010212001122202121012 |
4 | 100131201130231002221 |
5 | 122013210044011241 |
6 | 2223401000153305 |
7 | 144504320341055 |
oct | 20354134550251 |
9 | 4003761582535 |
10 | 1131211313321 |
11 | 3a6820328711 |
12 | 1632a0468835 |
13 | 828990c60cb |
14 | 3ca72748c65 |
15 | 1e65aaec6eb |
hex | 1076172d0a9 |
1131211313321 has 4 divisors (see below), whose sum is σ = 1131264385872. Its totient is φ = 1131158240772.
The previous prime is 1131211313263. The next prime is 1131211313327. The reversal of 1131211313321 is 1233131121311.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1131211313321 - 26 = 1131211313257 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1131211313327) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26504291 + ... + 26546936.
It is an arithmetic number, because the mean of its divisors is an integer number (282816096468).
Almost surely, 21131211313321 is an apocalyptic number.
It is an amenable number.
1131211313321 is a deficient number, since it is larger than the sum of its proper divisors (53072551).
1131211313321 is an equidigital number, since it uses as much as digits as its factorization.
1131211313321 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 53072550.
The product of its digits is 324, while the sum is 23.
Adding to 1131211313321 its reverse (1233131121311), we get a palindrome (2364342434632).
The spelling of 1131211313321 in words is "one trillion, one hundred thirty-one billion, two hundred eleven million, three hundred thirteen thousand, three hundred twenty-one".
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