Base | Representation |
---|---|
bin | 11001101110001000010101… |
… | …000100101110010111110100 |
3 | 112211112021121002010212022100 |
4 | 121232020111010232113310 |
5 | 104311334210230431400 |
6 | 1040331055103102100 |
7 | 32553510562505511 |
oct | 3156102504562764 |
9 | 484467532125270 |
10 | 113121202202100 |
11 | 33053483641244 |
12 | 1082b7918a1930 |
13 | 4b1738c0a12c1 |
14 | 1dd1149ac4308 |
15 | d1281e730100 |
hex | 66e21512e5f4 |
113121202202100 has 648 divisors, whose sum is σ = 368839944607680. Its totient is φ = 28989930977280.
The previous prime is 113121202202033. The next prime is 113121202202231. The reversal of 113121202202100 is 1202202121311.
113121202202100 is a `hidden beast` number, since 1 + 1 + 312 + 120 + 2 + 20 + 210 + 0 = 666.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 215 ways as a sum of consecutive naturals, for example, 46686421489 + ... + 46686423911.
Almost surely, 2113121202202100 is an apocalyptic number.
113121202202100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 113121202202100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (184419972303840).
113121202202100 is an abundant number, since it is smaller than the sum of its proper divisors (255718742405580).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113121202202100 is a wasteful number, since it uses less digits than its factorization.
113121202202100 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2921 (or 2858 counting only the distinct ones).
The product of its (nonzero) digits is 96, while the sum is 18.
Adding to 113121202202100 its reverse (1202202121311), we get a palindrome (114323404323411).
The spelling of 113121202202100 in words is "one hundred thirteen trillion, one hundred twenty-one billion, two hundred two million, two hundred two thousand, one hundred".
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