Base | Representation |
---|---|
bin | 11001101110001000010101… |
… | …100110101101001001110000 |
3 | 112211112021121200220102122120 |
4 | 121232020111212231021300 |
5 | 104311334220021010000 |
6 | 1040331100022034240 |
7 | 32553511031306202 |
oct | 3156102546551160 |
9 | 484467550812576 |
10 | 113121211110000 |
11 | 33053488675945 |
12 | 1082b794878980 |
13 | 4b17390b9ca52 |
14 | 1dd114ad62772 |
15 | d128203de6a0 |
hex | 66e2159ad270 |
113121211110000 has 200 divisors, whose sum is σ = 375039824952144. Its totient is φ = 29350368000000.
The previous prime is 113121211109993. The next prime is 113121211110071. The reversal of 113121211110000 is 11112121311.
It is a tau number, because it is divible by the number of its divisors (200).
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 49845501 + ... + 52065500.
Almost surely, 2113121211110000 is an apocalyptic number.
113121211110000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
113121211110000 is an abundant number, since it is smaller than the sum of its proper divisors (261918613842144).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113121211110000 is a wasteful number, since it uses less digits than its factorization.
113121211110000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 101911069 (or 101911048 counting only the distinct ones).
The product of its (nonzero) digits is 12, while the sum is 15.
Adding to 113121211110000 its reverse (11112121311), we get a palindrome (113132323231311).
The spelling of 113121211110000 in words is "one hundred thirteen trillion, one hundred twenty-one billion, two hundred eleven million, one hundred ten thousand".
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