Base | Representation |
---|---|
bin | 1010010010011100111100… |
… | …0000111001110111011111 |
3 | 1111001102120020021200011201 |
4 | 2210213033000321313133 |
5 | 2440314211213323403 |
6 | 40020414521300331 |
7 | 2245162633411144 |
oct | 244471700716737 |
9 | 44042506250151 |
10 | 11312122011103 |
11 | 3671497a72601 |
12 | 13284469346a7 |
13 | 6409617668a4 |
14 | 2b171c5b63cb |
15 | 1493c318a21d |
hex | a49cf039ddf |
11312122011103 has 4 divisors (see below), whose sum is σ = 11315518028248. Its totient is φ = 11308725993960.
The previous prime is 11312122011083. The next prime is 11312122011121. The reversal of 11312122011103 is 30111022121311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11312122011103 - 225 = 11312088456671 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11312122011143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1698003576 + ... + 1698010237.
It is an arithmetic number, because the mean of its divisors is an integer number (2828879507062).
Almost surely, 211312122011103 is an apocalyptic number.
11312122011103 is a deficient number, since it is larger than the sum of its proper divisors (3396017145).
11312122011103 is an equidigital number, since it uses as much as digits as its factorization.
11312122011103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3396017144.
The product of its (nonzero) digits is 72, while the sum is 19.
Adding to 11312122011103 its reverse (30111022121311), we get a palindrome (41423144132414).
The spelling of 11312122011103 in words is "eleven trillion, three hundred twelve billion, one hundred twenty-two million, eleven thousand, one hundred three".
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