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11312132141 = 44325535287
BaseRepresentation
bin10101000100100000…
…10111000000101101
31002012100202212001002
422202100113000231
5141131401212031
65110254130045
7550216352042
oct124220270055
932170685032
1011312132141
114885449342
1222384b0925
1310b37b261b
147945211c9
15463197ccb
hex2a241702d

11312132141 has 4 divisors (see below), whose sum is σ = 11337667872. Its totient is φ = 11286596412.

The previous prime is 11312132123. The next prime is 11312132179. The reversal of 11312132141 is 14123121311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11312132141 - 226 = 11245023277 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11312132191) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12767201 + ... + 12768086.

It is an arithmetic number, because the mean of its divisors is an integer number (2834416968).

Almost surely, 211312132141 is an apocalyptic number.

It is an amenable number.

11312132141 is a deficient number, since it is larger than the sum of its proper divisors (25535731).

11312132141 is an equidigital number, since it uses as much as digits as its factorization.

11312132141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 25535730.

The product of its digits is 144, while the sum is 20.

Adding to 11312132141 its reverse (14123121311), we get a palindrome (25435253452).

The spelling of 11312132141 in words is "eleven billion, three hundred twelve million, one hundred thirty-two thousand, one hundred forty-one".

Divisors: 1 443 25535287 11312132141