Base | Representation |
---|---|
bin | 10101000100100000… |
… | …10111000010010011 |
3 | 1002012100202212011212 |
4 | 22202100113002103 |
5 | 141131401212433 |
6 | 5110254130335 |
7 | 550216352246 |
oct | 124220270223 |
9 | 32170685155 |
10 | 11312132243 |
11 | 4885449425 |
12 | 22384b09ab |
13 | 10b37b2699 |
14 | 79452125d |
15 | 463197d48 |
hex | 2a2417093 |
11312132243 has 4 divisors (see below), whose sum is σ = 11314139688. Its totient is φ = 11310124800.
The previous prime is 11312132219. The next prime is 11312132261. The reversal of 11312132243 is 34223121311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11312132243 - 26 = 11312132179 is a prime.
It is a super-2 number, since 2×113121322432 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11312132203) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 995246 + ... + 1006547.
It is an arithmetic number, because the mean of its divisors is an integer number (2828534922).
Almost surely, 211312132243 is an apocalyptic number.
11312132243 is a deficient number, since it is larger than the sum of its proper divisors (2007445).
11312132243 is an equidigital number, since it uses as much as digits as its factorization.
11312132243 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2007444.
The product of its digits is 864, while the sum is 23.
Adding to 11312132243 its reverse (34223121311), we get a palindrome (45535253554).
The spelling of 11312132243 in words is "eleven billion, three hundred twelve million, one hundred thirty-two thousand, two hundred forty-three".
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