Base | Representation |
---|---|
bin | 100001101101101… |
… | …0000110010100101 |
3 | 2220211120221021222 |
4 | 1003123100302211 |
5 | 4304043021013 |
6 | 304125550125 |
7 | 40014132611 |
oct | 10333206245 |
9 | 2824527258 |
10 | 1131220133 |
11 | 5305a947a |
12 | 276a15345 |
13 | 150492134 |
14 | aa348341 |
15 | 694a1508 |
hex | 436d0ca5 |
1131220133 has 2 divisors, whose sum is σ = 1131220134. Its totient is φ = 1131220132.
The previous prime is 1131220127. The next prime is 1131220141. The reversal of 1131220133 is 3310221311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1082541604 + 48678529 = 32902^2 + 6977^2 .
It is an emirp because it is prime and its reverse (3310221311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1131220133 - 216 = 1131154597 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1131220183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565610066 + 565610067.
It is an arithmetic number, because the mean of its divisors is an integer number (565610067).
Almost surely, 21131220133 is an apocalyptic number.
It is an amenable number.
1131220133 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131220133 is an equidigital number, since it uses as much as digits as its factorization.
1131220133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 17.
The square root of 1131220133 is about 33633.6161154283. The cubic root of 1131220133 is about 1041.9551893791.
Adding to 1131220133 its reverse (3310221311), we get a palindrome (4441441444).
The spelling of 1131220133 in words is "one billion, one hundred thirty-one million, two hundred twenty thousand, one hundred thirty-three".
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