Base | Representation |
---|---|
bin | 10101000100100001… |
… | …01010000110010001 |
3 | 1002012100220211021122 |
4 | 22202100222012101 |
5 | 141131411212241 |
6 | 5110255532025 |
7 | 550220126006 |
oct | 124220520621 |
9 | 32170824248 |
10 | 11312210321 |
11 | 48854a2055 |
12 | 223852a015 |
13 | 10b380c099 |
14 | 7945418ad |
15 | 4631b104b |
hex | 2a242a191 |
11312210321 has 2 divisors, whose sum is σ = 11312210322. Its totient is φ = 11312210320.
The previous prime is 11312210303. The next prime is 11312210333. The reversal of 11312210321 is 12301221311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11193640000 + 118570321 = 105800^2 + 10889^2 .
It is a cyclic number.
It is not a de Polignac number, because 11312210321 - 218 = 11311948177 is a prime.
It is a super-2 number, since 2×113122103212 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 11312210321.
It is not a weakly prime, because it can be changed into another prime (11312212321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656105160 + 5656105161.
It is an arithmetic number, because the mean of its divisors is an integer number (5656105161).
Almost surely, 211312210321 is an apocalyptic number.
It is an amenable number.
11312210321 is a deficient number, since it is larger than the sum of its proper divisors (1).
11312210321 is an equidigital number, since it uses as much as digits as its factorization.
11312210321 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 11312210321 its reverse (12301221311), we get a palindrome (23613431632).
The spelling of 11312210321 in words is "eleven billion, three hundred twelve million, two hundred ten thousand, three hundred twenty-one".
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