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113122311013253 is a prime number
BaseRepresentation
bin11001101110001001010111…
…001010100000001110000101
3112211112101110100120022021002
4121232021113022200032011
5104311343443104411003
61040331401112503045
732553550215320213
oct3156112712401605
9484471410508232
10113122311013253
11330539a25244a3
121082ba410aaa85
134b17507a18689
141dd1213077cb3
15d12886c56a88
hex66e2572a0385

113122311013253 has 2 divisors, whose sum is σ = 113122311013254. Its totient is φ = 113122311013252.

The previous prime is 113122311013199. The next prime is 113122311013273. The reversal of 113122311013253 is 352310113221311.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 109638029589124 + 3484281424129 = 10470818^2 + 1866623^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-113122311013253 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113122311013273) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56561155506626 + 56561155506627.

It is an arithmetic number, because the mean of its divisors is an integer number (56561155506627).

Almost surely, 2113122311013253 is an apocalyptic number.

It is an amenable number.

113122311013253 is a deficient number, since it is larger than the sum of its proper divisors (1).

113122311013253 is an equidigital number, since it uses as much as digits as its factorization.

113122311013253 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3240, while the sum is 29.

Adding to 113122311013253 its reverse (352310113221311), we get a palindrome (465432424234564).

The spelling of 113122311013253 in words is "one hundred thirteen trillion, one hundred twenty-two billion, three hundred eleven million, thirteen thousand, two hundred fifty-three".