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11312301201283 is a prime number
BaseRepresentation
bin1010010010011101100110…
…1100011101011110000011
31111001110000201110110220001
42210213121230131132003
52440320043101420113
640020444402100431
72245200240454405
oct244473154353603
944043021413801
1011312301201283
11367157a131865
12132849694a717
1364098c915c94
142b17382dcb75
151493d3c837dd
hexa49d9b1d783

11312301201283 has 2 divisors, whose sum is σ = 11312301201284. Its totient is φ = 11312301201282.

The previous prime is 11312301201281. The next prime is 11312301201317. The reversal of 11312301201283 is 38210210321311.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11312301201283 - 21 = 11312301201281 is a prime.

Together with 11312301201281, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (11312301201281) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656150600641 + 5656150600642.

It is an arithmetic number, because the mean of its divisors is an integer number (5656150600642).

Almost surely, 211312301201283 is an apocalyptic number.

11312301201283 is a deficient number, since it is larger than the sum of its proper divisors (1).

11312301201283 is an equidigital number, since it uses as much as digits as its factorization.

11312301201283 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 28.

Adding to 11312301201283 its reverse (38210210321311), we get a palindrome (49522511522594).

The spelling of 11312301201283 in words is "eleven trillion, three hundred twelve billion, three hundred one million, two hundred one thousand, two hundred eighty-three".