Base | Representation |
---|---|
bin | 1010010010011101100110… |
… | …1100011101011110000011 |
3 | 1111001110000201110110220001 |
4 | 2210213121230131132003 |
5 | 2440320043101420113 |
6 | 40020444402100431 |
7 | 2245200240454405 |
oct | 244473154353603 |
9 | 44043021413801 |
10 | 11312301201283 |
11 | 367157a131865 |
12 | 132849694a717 |
13 | 64098c915c94 |
14 | 2b17382dcb75 |
15 | 1493d3c837dd |
hex | a49d9b1d783 |
11312301201283 has 2 divisors, whose sum is σ = 11312301201284. Its totient is φ = 11312301201282.
The previous prime is 11312301201281. The next prime is 11312301201317. The reversal of 11312301201283 is 38210210321311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11312301201283 - 21 = 11312301201281 is a prime.
Together with 11312301201281, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (11312301201281) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656150600641 + 5656150600642.
It is an arithmetic number, because the mean of its divisors is an integer number (5656150600642).
Almost surely, 211312301201283 is an apocalyptic number.
11312301201283 is a deficient number, since it is larger than the sum of its proper divisors (1).
11312301201283 is an equidigital number, since it uses as much as digits as its factorization.
11312301201283 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1728, while the sum is 28.
Adding to 11312301201283 its reverse (38210210321311), we get a palindrome (49522511522594).
The spelling of 11312301201283 in words is "eleven trillion, three hundred twelve billion, three hundred one million, two hundred one thousand, two hundred eighty-three".
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