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113123211300 = 2232521123894783
BaseRepresentation
bin110100101011010101…
…0110011100000100100
3101210222202021112211200
41221112222303200210
53323134020230200
6123545035002500
711113204300521
oct1512652634044
9353882245750
10113123211300
1143a80115a80
1219b10899430
13a88a590c28
145691d00148
152e213c8800
hex1a56ab3824

113123211300 has 216 divisors, whose sum is σ = 387055643520. Its totient is φ = 27406598400.

The previous prime is 113123211287. The next prime is 113123211301. The reversal of 113123211300 is 3112321311.

113123211300 is a `hidden beast` number, since 1 + 1 + 312 + 321 + 1 + 30 + 0 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is not an unprimeable number, because it can be changed into a prime (113123211301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 23648709 + ... + 23653491.

Almost surely, 2113123211300 is an apocalyptic number.

113123211300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 113123211300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (193527821760).

113123211300 is an abundant number, since it is smaller than the sum of its proper divisors (273932432220).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113123211300 is a wasteful number, since it uses less digits than its factorization.

113123211300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7203 (or 7193 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 113123211300 its reverse (3112321311), we get a palindrome (116235532611).

It can be divided in two parts, 113123 and 211300, that added together give a palindrome (324423).

The spelling of 113123211300 in words is "one hundred thirteen billion, one hundred twenty-three million, two hundred eleven thousand, three hundred".